set eol-style:native
[reactos.git] / reactos / lib / libxml2 / example / gjobread.c
1 /*
2 * gjobread.c : a small test program for gnome jobs XML format
3 *
4 * See Copyright for the status of this software.
5 *
6 * Daniel.Veillard@w3.org
7 */
8
9 #include <stdio.h>
10 #include <string.h>
11 #include <stdlib.h>
12
13 /*
14 * This example should compile and run indifferently with libxml-1.8.8 +
15 * and libxml2-2.1.0 +
16 * Check the COMPAT comments below
17 */
18
19 /*
20 * COMPAT using xml-config --cflags to get the include path this will
21 * work with both
22 */
23 #include <libxml/xmlmemory.h>
24 #include <libxml/parser.h>
25
26 #define DEBUG(x) printf(x)
27
28 /*
29 * A person record
30 * an xmlChar * is really an UTF8 encoded char string (0 terminated)
31 */
32 typedef struct person {
33 xmlChar *name;
34 xmlChar *email;
35 xmlChar *company;
36 xmlChar *organisation;
37 xmlChar *smail;
38 xmlChar *webPage;
39 xmlChar *phone;
40 } person, *personPtr;
41
42 /*
43 * And the code needed to parse it
44 */
45 static personPtr
46 parsePerson(xmlDocPtr doc, xmlNsPtr ns, xmlNodePtr cur) {
47 personPtr ret = NULL;
48
49 DEBUG("parsePerson\n");
50 /*
51 * allocate the struct
52 */
53 ret = (personPtr) malloc(sizeof(person));
54 if (ret == NULL) {
55 fprintf(stderr,"out of memory\n");
56 return(NULL);
57 }
58 memset(ret, 0, sizeof(person));
59
60 /* We don't care what the top level element name is */
61 /* COMPAT xmlChildrenNode is a macro unifying libxml1 and libxml2 names */
62 cur = cur->xmlChildrenNode;
63 while (cur != NULL) {
64 if ((!xmlStrcmp(cur->name, (const xmlChar *)"Person")) &&
65 (cur->ns == ns))
66 ret->name = xmlNodeListGetString(doc, cur->xmlChildrenNode, 1);
67 if ((!xmlStrcmp(cur->name, (const xmlChar *)"Email")) &&
68 (cur->ns == ns))
69 ret->email = xmlNodeListGetString(doc, cur->xmlChildrenNode, 1);
70 cur = cur->next;
71 }
72
73 return(ret);
74 }
75
76 /*
77 * and to print it
78 */
79 static void
80 printPerson(personPtr cur) {
81 if (cur == NULL) return;
82 printf("------ Person\n");
83 if (cur->name) printf(" name: %s\n", cur->name);
84 if (cur->email) printf(" email: %s\n", cur->email);
85 if (cur->company) printf(" company: %s\n", cur->company);
86 if (cur->organisation) printf(" organisation: %s\n", cur->organisation);
87 if (cur->smail) printf(" smail: %s\n", cur->smail);
88 if (cur->webPage) printf(" Web: %s\n", cur->webPage);
89 if (cur->phone) printf(" phone: %s\n", cur->phone);
90 printf("------\n");
91 }
92
93 /*
94 * a Description for a Job
95 */
96 typedef struct job {
97 xmlChar *projectID;
98 xmlChar *application;
99 xmlChar *category;
100 personPtr contact;
101 int nbDevelopers;
102 personPtr developers[100]; /* using dynamic alloc is left as an exercise */
103 } job, *jobPtr;
104
105 /*
106 * And the code needed to parse it
107 */
108 static jobPtr
109 parseJob(xmlDocPtr doc, xmlNsPtr ns, xmlNodePtr cur) {
110 jobPtr ret = NULL;
111
112 DEBUG("parseJob\n");
113 /*
114 * allocate the struct
115 */
116 ret = (jobPtr) malloc(sizeof(job));
117 if (ret == NULL) {
118 fprintf(stderr,"out of memory\n");
119 return(NULL);
120 }
121 memset(ret, 0, sizeof(job));
122
123 /* We don't care what the top level element name is */
124 cur = cur->xmlChildrenNode;
125 while (cur != NULL) {
126
127 if ((!xmlStrcmp(cur->name, (const xmlChar *) "Project")) &&
128 (cur->ns == ns)) {
129 ret->projectID = xmlGetProp(cur, (const xmlChar *) "ID");
130 if (ret->projectID == NULL) {
131 fprintf(stderr, "Project has no ID\n");
132 }
133 }
134 if ((!xmlStrcmp(cur->name, (const xmlChar *) "Application")) &&
135 (cur->ns == ns))
136 ret->application =
137 xmlNodeListGetString(doc, cur->xmlChildrenNode, 1);
138 if ((!xmlStrcmp(cur->name, (const xmlChar *) "Category")) &&
139 (cur->ns == ns))
140 ret->category =
141 xmlNodeListGetString(doc, cur->xmlChildrenNode, 1);
142 if ((!xmlStrcmp(cur->name, (const xmlChar *) "Contact")) &&
143 (cur->ns == ns))
144 ret->contact = parsePerson(doc, ns, cur);
145 cur = cur->next;
146 }
147
148 return(ret);
149 }
150
151 /*
152 * and to print it
153 */
154 static void
155 printJob(jobPtr cur) {
156 int i;
157
158 if (cur == NULL) return;
159 printf("======= Job\n");
160 if (cur->projectID != NULL) printf("projectID: %s\n", cur->projectID);
161 if (cur->application != NULL) printf("application: %s\n", cur->application);
162 if (cur->category != NULL) printf("category: %s\n", cur->category);
163 if (cur->contact != NULL) printPerson(cur->contact);
164 printf("%d developers\n", cur->nbDevelopers);
165
166 for (i = 0;i < cur->nbDevelopers;i++) printPerson(cur->developers[i]);
167 printf("======= \n");
168 }
169
170 /*
171 * A pool of Gnome Jobs
172 */
173 typedef struct gjob {
174 int nbJobs;
175 jobPtr jobs[500]; /* using dynamic alloc is left as an exercise */
176 } gJob, *gJobPtr;
177
178
179 static gJobPtr
180 parseGjobFile(char *filename) {
181 xmlDocPtr doc;
182 gJobPtr ret;
183 jobPtr curjob;
184 xmlNsPtr ns;
185 xmlNodePtr cur;
186
187 #ifdef LIBXML_SAX1_ENABLED
188 /*
189 * build an XML tree from a the file;
190 */
191 doc = xmlParseFile(filename);
192 if (doc == NULL) return(NULL);
193 #else
194 /*
195 * the library has been compiled without some of the old interfaces
196 */
197 return(NULL);
198 #endif /* LIBXML_SAX1_ENABLED */
199
200 /*
201 * Check the document is of the right kind
202 */
203
204 cur = xmlDocGetRootElement(doc);
205 if (cur == NULL) {
206 fprintf(stderr,"empty document\n");
207 xmlFreeDoc(doc);
208 return(NULL);
209 }
210 ns = xmlSearchNsByHref(doc, cur,
211 (const xmlChar *) "http://www.gnome.org/some-location");
212 if (ns == NULL) {
213 fprintf(stderr,
214 "document of the wrong type, GJob Namespace not found\n");
215 xmlFreeDoc(doc);
216 return(NULL);
217 }
218 if (xmlStrcmp(cur->name, (const xmlChar *) "Helping")) {
219 fprintf(stderr,"document of the wrong type, root node != Helping");
220 xmlFreeDoc(doc);
221 return(NULL);
222 }
223
224 /*
225 * Allocate the structure to be returned.
226 */
227 ret = (gJobPtr) malloc(sizeof(gJob));
228 if (ret == NULL) {
229 fprintf(stderr,"out of memory\n");
230 xmlFreeDoc(doc);
231 return(NULL);
232 }
233 memset(ret, 0, sizeof(gJob));
234
235 /*
236 * Now, walk the tree.
237 */
238 /* First level we expect just Jobs */
239 cur = cur->xmlChildrenNode;
240 while ( cur && xmlIsBlankNode ( cur ) )
241 {
242 cur = cur -> next;
243 }
244 if ( cur == 0 )
245 return ( NULL );
246 if ((xmlStrcmp(cur->name, (const xmlChar *) "Jobs")) || (cur->ns != ns)) {
247 fprintf(stderr,"document of the wrong type, was '%s', Jobs expected",
248 cur->name);
249 fprintf(stderr,"xmlDocDump follows\n");
250 #ifdef LIBXML_OUTPUT_ENABLED
251 xmlDocDump ( stderr, doc );
252 fprintf(stderr,"xmlDocDump finished\n");
253 #endif /* LIBXML_OUTPUT_ENABLED */
254 xmlFreeDoc(doc);
255 free(ret);
256 return(NULL);
257 }
258
259 /* Second level is a list of Job, but be laxist */
260 cur = cur->xmlChildrenNode;
261 while (cur != NULL) {
262 if ((!xmlStrcmp(cur->name, (const xmlChar *) "Job")) &&
263 (cur->ns == ns)) {
264 curjob = parseJob(doc, ns, cur);
265 if (curjob != NULL)
266 ret->jobs[ret->nbJobs++] = curjob;
267 if (ret->nbJobs >= 500) break;
268 }
269 cur = cur->next;
270 }
271
272 return(ret);
273 }
274
275 static void
276 handleGjob(gJobPtr cur) {
277 int i;
278
279 /*
280 * Do whatever you want and free the structure.
281 */
282 printf("%d Jobs registered\n", cur->nbJobs);
283 for (i = 0; i < cur->nbJobs; i++) printJob(cur->jobs[i]);
284 }
285
286 int main(int argc, char **argv) {
287 int i;
288 gJobPtr cur;
289
290 /* COMPAT: Do not genrate nodes for formatting spaces */
291 LIBXML_TEST_VERSION
292 xmlKeepBlanksDefault(0);
293
294 for (i = 1; i < argc ; i++) {
295 cur = parseGjobFile(argv[i]);
296 if ( cur )
297 handleGjob(cur);
298 else
299 fprintf( stderr, "Error parsing file '%s'\n", argv[i]);
300
301 }
302
303 /* Clean up everything else before quitting. */
304 xmlCleanupParser();
305
306 return(0);
307 }