/*********************************************************************
* $I10_OUTPUT (MSVCRT.@)
- * ld - long double to be printed to data
+ * ld80 - long double (Intel 80 bit FP in 12 bytes) to be printed to data
* prec - precision of part, we're interested in
* flag - 0 for first prec digits, 1 for fractional part
* data - data to be populated
* Native sets last byte of data->str to '0' or '9', I don't know what
* it means. Current implementation sets it always to '0'.
*/
-int CDECL MSVCRT_I10_OUTPUT(long double ld, int prec, int flag, struct _I10_OUTPUT_DATA *data)
+int CDECL MSVCRT_I10_OUTPUT(_LDOUBLE ld80, int prec, int flag, struct _I10_OUTPUT_DATA *data)
{
static const char inf_str[] = "1#INF";
static const char nan_str[] = "1#QNAN";
- double d = ld;
+ /* MS' long double type wants 12 bytes for Intel's 80 bit FP format.
+ * Some UNIX have sizeof(long double) == 16, yet only 80 bit are used.
+ * Assume long double uses 80 bit FP, never seen 128 bit FP. */
+ long double ld = 0;
+ double d;
char format[8];
char buf[I10_OUTPUT_MAX_PREC+9]; /* 9 = strlen("0.e+0000") + '\0' */
char *p;
+ memcpy(&ld, &ld80, 10);
+ d = ld;
TRACE("(%lf %d %x %p)\n", d, prec, flag, data);
if(d<0) {
}
if(flag&1) {
- int exp = (int)(1+floor(log10(d)));
+ int exp = 1+floor(log10(d));
prec += exp;
if(exp < 0)
data->pos++;
for(p = buf+prec+1; p>buf+1 && *p=='0'; p--);
- data->len = (BYTE)(p - buf);
+ data->len = p-buf;
memcpy(data->str, buf+1, data->len);
data->str[data->len] = '\0';